(x+4)(x^2-3x+2)=0

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Solution for (x+4)(x^2-3x+2)=0 equation: 


Simplifying
(x + 4)(x2 + -3x + 2) = 0

Reorder the terms:
(4 + x)(x2 + -3x + 2) = 0

Reorder the terms:
(4 + x)(2 + -3x + x2) = 0

Multiply (4 + x) * (2 + -3x + x2)
(4(2 + -3x + x2) + x(2 + -3x + x2)) = 0
((2 * 4 + -3x * 4 + x2 * 4) + x(2 + -3x + x2)) = 0
((8 + -12x + 4x2) + x(2 + -3x + x2)) = 0
(8 + -12x + 4x2 + (2 * x + -3x * x + x2 * x)) = 0
(8 + -12x + 4x2 + (2x + -3x2 + x3)) = 0

Reorder the terms:
(8 + -12x + 2x + 4x2 + -3x2 + x3) = 0

Combine like terms: -12x + 2x = -10x
(8 + -10x + 4x2 + -3x2 + x3) = 0

Combine like terms: 4x2 + -3x2 = 1x2
(8 + -10x + 1x2 + x3) = 0

Solving
8 + -10x + 1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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